Knowing that a function named f() resides in a module named m, and was imported using the following statement
from mod import fun
choose the right way to invoke it:
- fun()
- mod.fun()
- mod::fun()
- mod:fun()
What output will appear after running the following snippet?
import math
print(dir(math))
- an error message
- a string containing the fully qualified name of the module
- a list of all the entities residing in the math module
- the number of all the entities residing in the math module
The compiled Python bytecode is stored in files having names ending with:
Assuming that all three files, a.py, b.py, and c.py reside in the same folder, what will be the output produced by running the c.py file?
# file a.py
print(“a”,end=”)
#file b.py
import a
print(“b”,end=”)
#file c.py
print(“c”,end=”)
import a
import b
What will be the output of the following code, located in file p.py?
print(__name__)
- p.py
- main
- __p.py__
- __main__
The following statement
from a.b import c
causes the import of:
- entity a from module b from package c
- entity b from module a from package c
- entity c from module b from package a
- entity c from module a from package b
If there are more than one except: branches after the try:, we can say that:
- one or more of the try: blocks will be executed
- none of the try: blocks will be executed
- not more than one try: block will be executed
- exactly one of the try: blocks will be executed
- What will be the output of the following snippet? try: raise Exception
except BaseException:
print(“a”)
except Exception:
print(“b”)
except:
print(“c”)
- c
- b
- it will cause an error
- a
The following line of code:
for line in open(‘text.txt’,’rt’):
- is valid as open returns an iterable object
- is invalid as open returns a non-iterable object
- is invalid as open returns nothing
- may be valid if line is a list
What will be the output of the following snippet?
try:
raise Exception
except:
print(“c”)
except BaseException:
print(“a”)
except Exception:
print(“b”)
- a
- c
- b
- it will cause an error
The following statement:
assert var != 0
- will stop the program when var == 0
- is erroneous
- has no effect
- will stop the program when var != 0
The following code prints:
x = “\\\\”
print(len(x))
- 2
- 1
- 3
- the code will cause an error
The following code prints:
x = “\\\”
print(len(x))
- 3
- the code will cause an error
- 1
- 2
The following code prints:
print(chr(ord(‘p’) + 2))
The following code:
print(float(“1.3”))
- raises a ValueError exception
- prints 13
- prints 1,3
- 1.3
If the class’s constructor is declared as below, which one of the assignments is invalid?
class Class:
def __init__(self,val=0):
pass
- object = Class(None)
- object = Class(1)
- object = Class()
- object = Class(1,2)
What will be output of the following code?
class A:
def __init__(self,v = 2):
self.v = v
def set(self,v = 1):
self.v += v
return self.v
a = A()
b = a
b.set()
print(a.v)
What will be output of the following code?
class A:
A = 1
def __init__(self):
self.a = 0
print(hasattr(A,’a’))
What will be the result of executing the following code?
class A:
pass
class B(A):
pass
class C(B):
pass
print(issubclass(A,C))
- it will print False
- it will print True
- it will print 1
- it will raise an exception
The sys.stderr stream is normally associated with:
- the keyboard
- a null device
- the screen
- the printer
What will be the effect of running the following code?
class A:
def __init__(self,v):
self.__a = v + 1
a = A(0)
print(a.__a)
- it will print 1
- it will print 2
- it will raise an AttributeError exception
- it will print 0
What will be the result of executing the following code?
class A:
def __init__(self):
pass
a = A(1)
print(hasattr(a,’A’))
- it will print True
- it will raise an exception
- it will print False
- it will print 1
What will be the result of executing the following code?
class A:
def a(self):
print(‘a’)
class B:
def a(self):
print(‘b’)
class C(B,A):
def c(self):
self.a()
o = C()
o.c()
- it will print c
- it will raise an exception
- it will print b
- it will print a
What will be the result of executing the following code?
try:
raise Exception(1,2,3)
except Exception as e:
print(len(e.args))
- it will print 2
- it will print 1
- it will raise an unhandled exception
- it will print 3
What will be the result of executing the following code?
def I(n):
s = ‘+’
for i in range(n):
s += s
yield s
for x in I(2):
print(x,end=”)
- it will print ++
- it will print ++++++
- it will print +
- it will print +++
What will be the result of executing the following code?
class I:
def __init__(self):
self.s = ‘abc’
self.i = 0
def __iter__(self):
return self
def __next__(self):
if self.i == len(self.s):
raise StopIteration
v = self.s[self.i]
self.i += 1
return v
for x in I():
print(x,end=”)
What will be the result of executing the following code?
def o(p):
def q():
return ‘*’ * p
return q
r = o(1)
s = o(2)
print(r() + s())
- it will print ****
- it will print **
- it will print ***
- it will print *
If s is a stream opened in read mode, the following line will:
q = s.read(1)
- read 1 character from the stream
- read 1 kilobyte from the stream
- read 1 line from the stream
- read 1 buffer from the stream
Assuming that the open() invocation has gone successfully, the following snippet will:
for x in open(‘file’,’rt’):
print(x)
- read the file character by character
- cause an exception
- read the whole file at once
- read the file line by line
If you want to fill a byte array with data read in from a stream, you’d use:
- the readinto() method
- the read() method
- the readbytes() method
- the readfrom() method
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